-1.2x^2-3x+5.6=0

Solution for -1.2x^2-3x+5.6=0 equation:

-1.2x^2-3x+5.6=0

a = -1.2; b = -3; c = +5.6;
Δ = b2-4ac
Δ = -32-4·(-1.2)·5.6
Δ = 35.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{35.88}}{2*-1.2}=\frac{3-\sqrt{35.88}}{-2.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{35.88}}{2*-1.2}=\frac{3+\sqrt{35.88}}{-2.4}
$